In the previous section, we saw solid-vapour equilibrium and equilibrium in solutions. In this section, we will see the general characteristics of equilibrium
First let us write a summary of what we have learnt so far in the previous two sections. It can be written in 4 steps:
1. Solid-liquid equilibrium
(i) For a solid-liquid reversible process, we write: Solid ⇌ Liquid
♦ This process is called melting
(ii) For a given solid and it’s liquid, there exists a particular temperature at which equilibrium is possible
♦ This temperature is called melting point
(iii) This temperature depends on the pressure experienced by the system
• So if the experiment is conducted at different pressures, we will obtain different equilibrium temperatures
• In order to avoid such a confusion, we specify that, the experiment must be conducted at 1 atm pressure
(iv) Consider the process: Ice ⇌ Water
• For equilibrium of this process,
♦ temperature must be 0 оC
♦ pressure must be 1 atm
✰ If temperature is lower than 0 оC, the rate of forward process will increase
✰ If temperature is higher than 0 оC, the rate of backward process will increase
2. Solid-liquid equilibrium
(i) For a liquid-vapour reversible process, we write: Liquid ⇌ Vapour
♦ This process is called vaporization
(ii) For a given liquid and it’s vapour, there exists a particular temperature at which equilibrium is possible
♦ This temperature is called boiling point
(iii) This temperature depends on the pressure experienced by the system
• So if the experiment is conducted at different pressures, we will obtain different equilibrium temperatures
• In order to avoid such a confusion, we specify that, the experiment must be conducted at 1 atm pressure
(iv) Consider the process: Water ⇌ Vapour
• For equilibrium of this process,
♦ temperature must be 100 оC
♦ pressure must be 1 atm
✰ If temperature is lower than 100 оC, the rate of backward process will increase
✰ If temperature is higher than 0 оC, the rate of forward process will increase
3. Solid-solution equilibrium
(i) For a solid-solution reversible process, we write: Solid ⇌ Solution
♦ This process is called dissolution of solid in liquid
(ii) For a given solid and it’s solution, there exists a particular temperature at which equilibrium is possible
(iv) Consider the process: Sugar ⇌ Solution
• At a particular temperature, equilibrium exists between solid sugar and the sugar solution
♦ If temperature is lower, then the rate of backward process will increase
✰ Solid sugar will precipitate out of the solution
♦ If temperature is higher then the rate of forward process will increase
✰ Solid sugar will dissolve into the solution
4. Gas-solution equilibrium
(i) For a Gas-solution reversible process, we write: Gas ⇌ Solution
♦ This process is called dissolution of gas in liquid
(ii) For a given gas and it’s solution, there exists a particular pressure at which equilibrium is possible
(iv) Consider the process: CO2(g) ⇌ CO2(sol)
• At a particular pressure, equilibrium exists between CO2(g) and the CO2(sol)
♦ If pressure is lower, then the rate of backward process will increase
✰ CO2(g) will escape out of CO2(sol)
♦ If pressure is higher then the rate of forward process will increase
✰ CO2(g) will dissolve into the CO2(sol)
(v) This equilibrium pressure depends on temperature also
♦ If the temperature is lower, lesser pressure is sufficient to cause dissolution
♦ If the temperature is higher, greater pressure is required to cause dissolution
• This is because, at lower temperature, the gas molecules will not have sufficient energy to escape out of the solution
Based on the above summary, we can write 4 points:
1. For the equilibrium of Solid ⇌ Liquid, temperature is the criteria
♦ Also the pressure needs to be constant
• The temperature at any instant during the process will tell us:
♦ The direction in which, the process is going on
♦ The extent up to which the process has reached in that direction
• For example:
♦ If the temperature is lower than the specified value
✰ we can be sure that, the process will be taking place in the reverse direction
♦ If the temperature is much lower than the specified value
✰ we can be sure that, greater amount of solid will be present
2. For the equilibrium of Liquid ⇌ Vapour, temperature is the criteria
♦ Also the pressure needs to be constant
• The temperature at any instant during the process will tell us:
♦ The direction in which, the process is going on
♦ The extent up to which the process has reached in that direction
• For example:
♦ If the temperature is lower than the specified value
✰ we can be sure that, the process will be taking place in the reverse direction
♦ If the temperature is much lower than the specified value
✰ we can be sure that, greater amount of liquid will be present
3. For the equilibrium of Solid ⇌ Solution, temperature is the criteria
• The temperature at any instant during the process will tell us:
♦ The direction in which, the process is going on
♦ The extent up to which the process has reached in that direction
• For example:
♦ If the temperature is lower than the specified value
✰ we can be sure that, the process will be taking place in the reverse direction
♦ If the temperature is much lower than the specified value
✰ we can be sure that, greater amount of solid will be present
4. For the equilibrium of Gas ⇌ Solution, pressure is the criteria
♦ Also the temperature needs to be constant
• The pressure at any instant during the process will tell us:
♦ The direction in which, the process is going on
♦ The extent up to which the process has reached in that direction
• For example:
♦ If the pressure is lower than the specified value
✰ we can be sure that, the process will be taking place in the reverse direction
♦ If the pressure is much lower than the specified value
✰ we can be sure that, greater amount of free gas will be present
• We know that, equilibrium can occur in both physical processes and chemical reactions
• In both cases, equilibrium is dynamic. That is., although we observe no activity at equilibrium, forward and backward reactions are going on
♦ We can use radioactive isotopes to prove this
♦ We saw it in the case of sugar solution
• But a procedure using radioactive isotopes is not suitable for school laboratories
• So instead of using isotopes, we can do a simple activity. It can be explained in 11 steps:
1. Take two measuring cylinders, each of 100 mL capacity
♦ Mark them as Cylinder-1 and cylinder-2
2. Take two glass tubes, each of length 30 cm
♦ Both must have the same diameter of 3 or 4 mm
♦ Mark them as tube-1’ and tube-2’
• This is shown in fig.7.2 below:
Fig.7.2 |
3. Fill about half of cylinder-1 with coloured water
♦ Potassium permanganate can be used to color the water
• Keep the measuring cylinder-2 empty
4. Put tube-1’ in cylinder-1 and tube-2’ in cylinder-2
5. Close the upper tip of tube-1’ with finger
♦ Transfer this tube-1’ to cylinder-2 and open the tip
♦ The water in the tube-1’ will fall into cylinder-2
6. Close the upper tip of tube-2’ with finger
♦ Transfer this tube-2’ to cylinder-1 and open the tip
♦ The water in the tube-2’ will fall into cylinder-1
7. The quantity transferred in (5) will be greater than quantity transferred in (6)
• This is because:
♦ While in cylinder-1, the tube-1’ will take in more water
♦ While in cylinder-2, the tube-2’ will take in only less water
8. Keep repeating the steps (5) and (6)
• We will soon see that, the level in the cylinders become equal
• This is shown in fig.7.2(b)
9. Transfer using tube-1’ is the forward process
• In the early stages, the quantity in each of this transfer is high
• But the ‘quantity continuously decreases’ due to the lowering of level in cylinder-1
• This ‘continuous decrease in quantity’ is analogous to the ‘decrease in rate of forward process’
9. Transfer using tube-2’ is the backward process
• In the early stages, the quantity in each of this transfer is low
• But the ‘quantity continuously increases’ due to the rising of level in cylinder-2
• This ‘continuous increase in quantity’ is analogous to the ‘increase in rate of backward process’
10. So the two rates are not the same
♦ Rate of the forward process continuously decreases
♦ Rate of the backward process continuously increases
• Due to this, the two rates soon become equal
◼ When this happens, we get the equilibrium
◼ The levels becoming equal in step (8) is analogous to equilibrium
11.After reaching equilibrium, we can try repeating the steps (5) and (6)
• There will be no change in the levels
◼ In a real process/reaction also, even after equilibrium, the forward and backward processes/reactions are continuing. But we observe no change
•
In the next section, we will see equilibrium in chemical reactions
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